What is the first ((10)/x)^' ?

The first ((10)/x)^' is -(10)/(x^2)

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((10)/x)^'

(\frac{10}{x})^{^{'}}

- \frac{10}{x ^{2}}

Solution steps

(\frac{10}{x})^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 (\frac{1}{x})^{^{'}}

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 10 (x^{- 1})^{^{'}}

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 10 (- 1 \cdot x^{- 1 - 1})

Simplify

10 (- 1 \cdot x^{- 1 - 1}) : - \frac{10}{x ^{2}}

= - \frac{10}{x ^{2}}

x \to 8 - lim (\frac{x - 8}{x - 8})

x \to 12 lim (\frac{x - 12}{x ^{2} - 144})

\frac{s}{s ^{2} + 8 s + 25}

y = \frac{2 x + 3}{3 x - 2}, (1, 5)

f (x) = \frac{x - 3}{6 x - 1}, at x = 1