What is the tangent of y=(2x+3)/(3x-2),(1,5) ?

The tangent of y=(2x+3)/(3x-2),(1,5) is y=-13x+18

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tangent of y=(2x+3)/(3x-2),(1,5)

tangent of

y = \frac{2 x + 3}{3 x - 2}, (1, 5)

y = - 13 x + 18

Solution steps

Find the slope of

y = \frac{2 x + 3}{3 x - 2} : \frac{d y}{d x} = - \frac{13}{( 3 x - 2 ) ^{2}}

Compute the slope of

y = \frac{2 x + 3}{3 x - 2}

(1, 5) : m = - 13

Find the line with slope m=

- 13

and passing through

(1, 5) : y = - 13 x + 18

y = - 13 x + 18

f (x) = \frac{x - 3}{6 x - 1}, at x = 1

y^{^{''}} + 4 y^{^{'}} + 4 y = 12 t e^{- 2 t} + 4 t

(x + 2)^{2} + (y - 3)^{2} = 37, (- 1, 9)

\int tan (4 x) sec^{2} (4 x) d x

x^{2} - e^{y^{2}}

What is the tangent of y=(2x+3)/(3x-2),(1,5) ?
The tangent of y=(2x+3)/(3x-2),(1,5) is y=-13x+18