What is the derivative of x^2-e^{y^2} ?

The derivative of x^2-e^{y^2} is 2x

What is the first derivative of x^2-e^{y^2} ?

The first derivative of x^2-e^{y^2} is 2x

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derivative of

x^{2} - e^{y^{2}}

2 x

Solution steps

\frac{d}{d x} (x^{2} - e^{y^{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (e^{y^{2}})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{y^{2}}) = 0

= 2 x - 0

Simplify

= 2 x

y = arctan (e^{x})

\int 3 x^{2} - 6 x d x

f (x) = x^{2} + x - 56, g (x) = - x^{2} + 3 x + 4

1 + \frac{a}{r} - \frac{b}{r ^{3}}

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = x + x^{2} ln (x)

What is the derivative of x^2-e^{y^2} ?
The derivative of x^2-e^{y^2} is 2x
What is the first derivative of x^2-e^{y^2} ?
The first derivative of x^2-e^{y^2} is 2x