What is laplacetransform 5e^{-2t} ?

The answer to laplacetransform 5e^{-2t} is 5/(s+2)

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laplacetransform 5e^{-2t}

laplace transform

5 e^{- 2 t}

\frac{5}{s + 2}

Solution steps

L {5 e^{- 2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= 5 \cdot \frac{1}{s + 2}

Refine

5 \frac{1}{s + 2} : \frac{5}{s + 2}

= \frac{5}{s + 2}

y^{^{'}} = 12 t^{5} - 20 t^{4} + 2 - 6 t^{- 2}

y = t e^{- 3 t} sin (5 t)

\frac{( 3 x - 7 )}{( 9 x + 5 )} + x^{3}

\frac{\partial}{\partial y} (x^{2} y)

\int \frac{x}{2 - x ^{2}} d x

What is laplacetransform 5e^{-2t} ?
The answer to laplacetransform 5e^{-2t} is 5/(s+2)