What is the derivative of ((3x-7))/((9x+5))+x^3 ?

The derivative of ((3x-7))/((9x+5))+x^3 is (78)/((9x+5)^2)+3x^2

What is the first derivative of ((3x-7))/((9x+5))+x^3 ?

The first derivative of ((3x-7))/((9x+5))+x^3 is (78)/((9x+5)^2)+3x^2

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derivative of

\frac{( 3 x - 7 )}{( 9 x + 5 )} + x^{3}

\frac{78}{( 9 x + 5 ) ^{2}} + 3 x^{2}

Solution steps

\frac{d}{d x} (\frac{3 x - 7}{9 x + 5} + x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3 x - 7}{9 x + 5}) + \frac{d}{d x} (x^{3})

\frac{d}{d x} (\frac{3 x - 7}{9 x + 5}) = \frac{78}{( 9 x + 5 ) ^{2}}

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{78}{( 9 x + 5 ) ^{2}} + 3 x^{2}

\frac{\partial}{\partial y} (x^{2} y)

\int \frac{x}{2 - x ^{2}} d x

\frac{d}{d x} (- 3 sin (x - π) + x)

y^{^{'}} - 9 y = 27

\frac{d}{d x} (\frac{1}{5} x)

What is the derivative of ((3x-7))/((9x+5))+x^3 ?
The derivative of ((3x-7))/((9x+5))+x^3 is (78)/((9x+5)^2)+3x^2
What is the first derivative of ((3x-7))/((9x+5))+x^3 ?
The first derivative of ((3x-7))/((9x+5))+x^3 is (78)/((9x+5)^2)+3x^2