What is the integral from 2 to infinity of 1/(e^x) ?

The integral from 2 to infinity of 1/(e^x) is 1/(e^2)

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integral from 2 to infinity of 1/(e^x)

\int_{2}^{\infty} \frac{1}{e ^{x}} d x

\frac{1}{e ^{2}}

Decimal Notation

0.13533 \dots

Solution steps

\int_{2}^{\infty} \frac{1}{e ^{x}} d x

Compute the indefinite integral:

\int \frac{1}{e ^{x}} d x = - \frac{1}{e ^{x}} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{e ^{x}} d x = 0 - (- \frac{1}{e ^{2}})

= 0 - (- \frac{1}{e ^{2}})

Simplify

= \frac{1}{e ^{2}}

t \to - 2 lim (\frac{t + 2}{t ^{2} - 4})

x \frac{d y}{d x} + 10 y = 9 y^{2}, y (1) = - 1

\frac{d y}{d x} + 4 x^{2} y = - 10 x^{2}

\frac{d}{d x} (\frac{( x ^{4} + 2 )}{ln ( x )})

x \to 6 lim (\frac{x}{x - 6})

What is the integral from 2 to infinity of 1/(e^x) ?
The integral from 2 to infinity of 1/(e^x) is 1/(e^2)