Solution
Solution
Solution steps
Solve Bernoulli ODE:
Popular Examples
y^'=(x^2-y^2)/(xy),y(2)=5(\partial)/(\partial y)(e^{xyz^4}yz^4)(\partial)/(\partial y)(x^2-2xy+2y^2)tangent of f(x)=x^3-4x,(2,0)tangent of derivative of cos(x)-(sqrt(2))/2 xderivative of
Frequently Asked Questions (FAQ)
What is the solution for (x^2+y^2)dx+(2xy)dy=0 ?
The solution for (x^2+y^2)dx+(2xy)dy=0 is y=sqrt(-(x^2)/3+(c_{1))/x},y=-sqrt(-(x^2)/3+(c_{1))/x}