What is the derivative of pi(2t-3) ?

The derivative of pi(2t-3) is 2pi

What is the first derivative of pi(2t-3) ?

The first derivative of pi(2t-3) is 2pi

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derivative of

π (2 t - 3)

2 π

Solution steps

\frac{d}{d t} (π (2 t - 3))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= π \frac{d}{d t} (2 t - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= π (\frac{d}{d t} (2 t) - \frac{d}{d t} (3))

\frac{d}{d t} (2 t) = 2

\frac{d}{d t} (3) = 0

= π (2 - 0)

Simplify

= 2 π

ln (x - 2)

\frac{d}{d x} (\frac{3000}{x})

x \frac{d y}{d x} - 3 y = x^{3}

x \to 3 + lim (\frac{x}{x ^{2} - 4 x + 3})

x \to - 1 lim (3 x^{2} + 3 x^{3} + 10)

What is the derivative of pi(2t-3) ?
The derivative of pi(2t-3) is 2pi
What is the first derivative of pi(2t-3) ?
The first derivative of pi(2t-3) is 2pi