What is the derivative of f(x)=(1+2x^2)^2+2x^3 ?

The derivative of f(x)=(1+2x^2)^2+2x^3 is 8x(1+2x^2)+6x^2

What is the first derivative of f(x)=(1+2x^2)^2+2x^3 ?

The first derivative of f(x)=(1+2x^2)^2+2x^3 is 8x(1+2x^2)+6x^2

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derivative of

f (x) = (1 + 2 x^{2})^{2} + 2 x^{3}

8 x (1 + 2 x^{2}) + 6 x^{2}

Solution steps

\frac{d}{d x} ((1 + 2 x^{2})^{2} + 2 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} ((1 + 2 x^{2})^{2}) + \frac{d}{d x} (2 x^{3})

\frac{d}{d x} ((1 + 2 x^{2})^{2}) = 8 x (1 + 2 x^{2})

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

= 8 x (1 + 2 x^{2}) + 6 x^{2}

\int_{0}^{1} 1 + x^{3} d x

\frac{d}{d x} (arcsin (x) + x 1 - x^{2})

\frac{d}{d x} (4 x^{2} + 4 x^{3})

\int e^{- x} cos (7 x) d x

\frac{d}{d x} (ln (1 + 6 x))

What is the derivative of f(x)=(1+2x^2)^2+2x^3 ?
The derivative of f(x)=(1+2x^2)^2+2x^3 is 8x(1+2x^2)+6x^2
What is the first derivative of f(x)=(1+2x^2)^2+2x^3 ?
The first derivative of f(x)=(1+2x^2)^2+2x^3 is 8x(1+2x^2)+6x^2