What is the first derivative of e^x+1 ?

The first derivative of e^x+1 is e^x

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derivative of e^x+1

derivative of

e^{x} + 1

e^{x}

Solution steps

\frac{d}{d x} (e^{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (1)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (1) = 0

= e^{x} + 0

Simplify

= e^{x}

f (x) = x^{2} - 1, (5, 24)

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