What is the derivative of-9cos(3x) ?

The derivative of-9cos(3x) is 27sin(3x)

What is the first derivative of-9cos(3x) ?

The first derivative of-9cos(3x) is 27sin(3x)

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derivative of

- 9 cos (3 x)

27 sin (3 x)

Solution steps

\frac{d}{d x} (- 9 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 9 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 9 (- sin (3 x) \cdot 3)

Simplify

= 27 sin (3 x)

\int \frac{( x - 1 ) ^{2}}{2} d x

1 + t

\frac{\partial}{\partial x} (3 x^{3} + y^{3} - 12 x y)

x \to - 2 lim (7 x + 4)

x \to 8 - lim (\frac{5}{( x - 8 ) ^{2}})

What is the derivative of-9cos(3x) ?
The derivative of-9cos(3x) is 27sin(3x)
What is the first derivative of-9cos(3x) ?
The first derivative of-9cos(3x) is 27sin(3x)