What is the solution for y^{''}-10y^'+24y=0 ?

The solution for y^{''}-10y^'+24y=0 is y=c_{1}e^{6t}+c_{2}e^{4t}

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y^{''}-10y^'+24y=0

y^{^{''}} - 10 y^{^{'}} + 24 y = 0

y = c_{1} e^{6 t} + c_{2} e^{4 t}

Solution steps

y^{''} (t) - 10 y^{'} (t) + 24 y = 0

Solve linear ODE:

y = c_{1} e^{6 t} + c_{2} e^{4 t}

y = c_{1} e^{6 t} + c_{2} e^{4 t}

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What is the solution for y^{''}-10y^'+24y=0 ?
The solution for y^{''}-10y^'+24y=0 is y=c_{1}e^{6t}+c_{2}e^{4t}