What is the derivative of y=6cos(x+y) ?

The derivative of y=6cos(x+y) is -6sin(x+y)

What is the first derivative of y=6cos(x+y) ?

The first derivative of y=6cos(x+y) is -6sin(x+y)

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derivative of

y = 6 cos (x + y)

- 6 sin (x + y)

Solution steps

\frac{d}{d x} (6 cos (x + y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (cos (x + y))

Apply the chain rule:

- sin (x + y) \frac{d}{d x} (x + y)

= - sin (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1

= 6 (- sin (x + y) \cdot 1)

Simplify

= - 6 sin (x + y)

y^{^{''}} + 4 y = 2 sec (2 x)

\int e^{8 x + 6} d x

y^{^{'}} = \frac{( cos ( 18 x ) )}{( e ^{(18 \cdot y)} )}

x^{2} y^{^{''}} + 3 x y^{^{'}} - 3 y = 0

d y - (y - 9)^{2} d x = 0

What is the derivative of y=6cos(x+y) ?
The derivative of y=6cos(x+y) is -6sin(x+y)
What is the first derivative of y=6cos(x+y) ?
The first derivative of y=6cos(x+y) is -6sin(x+y)