What is the solution for x^2y^{''}+3xy^'-3y=0 ?

The solution for x^2y^{''}+3xy^'-3y=0 is y=c_{1}x+(c_{2})/(x^3)

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x^2y^{''}+3xy^'-3y=0

x^{2} y^{^{''}} + 3 x y^{^{'}} - 3 y = 0

y = c_{1} x + \frac{c _{2}}{x ^{3}}

Solution steps

x^{2} y^{''} (x) + 3 x y^{'} (x) - 3 y = 0

Solve linear ODE:

y = c_{1} x + \frac{c _{2}}{x ^{3}}

y = c_{1} x + \frac{c _{2}}{x ^{3}}

d y - (y - 9)^{2} d x = 0

x^{\frac{5}{6}}

\frac{x ( 2 - x )}{e ^{x}}

sec (2 x)

\int 2 y cos (y^{2}) d y

What is the solution for x^2y^{''}+3xy^'-3y=0 ?
The solution for x^2y^{''}+3xy^'-3y=0 is y=c_{1}x+(c_{2})/(x^3)