What is the derivative of (x(2-x))/(e^x) ?

The derivative of (x(2-x))/(e^x) is (2-4x+x^2)/(e^x)

What is the first derivative of (x(2-x))/(e^x) ?

The first derivative of (x(2-x))/(e^x) is (2-4x+x^2)/(e^x)

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derivative of

\frac{x ( 2 - x )}{e ^{x}}

\frac{2 - 4 x + x ^{2}}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{x ( 2 - x )}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ( 2 - x ) ) e ^{x} - \frac{d}{d x} ( e ^{x} ) x ( 2 - x )}{( e ^{x} ) ^{2}}

\frac{d}{d x} (x (2 - x)) = 2 - 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{( 2 - 2 x ) e ^{x} - e ^{x} x ( 2 - x )}{( e ^{x} ) ^{2}}

Simplify

\frac{( 2 - 2 x ) e ^{x} - e ^{x} x ( 2 - x )}{( e ^{x} ) ^{2}} : \frac{2 - 4 x + x ^{2}}{e ^{x}}

= \frac{2 - 4 x + x ^{2}}{e ^{x}}

sec (2 x)

\int 2 y cos (y^{2}) d y

10000 (12 + t) e^{- 0.05 t}

\int \frac{e ^{\frac{1}{x}}}{x} d x

f (x) = 4 x + 65, (4, 9)

What is the derivative of (x(2-x))/(e^x) ?
The derivative of (x(2-x))/(e^x) is (2-4x+x^2)/(e^x)
What is the first derivative of (x(2-x))/(e^x) ?
The first derivative of (x(2-x))/(e^x) is (2-4x+x^2)/(e^x)