What is 10000(12+t)e^{-0.05t} ?

The solution to 10000(12+t)e^{-0.05t} is (10000(t+12))/(e^{0.05t)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 10000(12+t)e^{-0.05t}

simplify

10000 (12 + t) e^{- 0.05 t}

\frac{10000 ( t + 12 )}{e ^{0.05 t}}

Solution steps

10000 (12 + t) e^{- 0.05 t}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= 10000 \cdot \frac{1}{e ^{0.05 t}} (t + 12)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 10000 ( 12 + t )}{e ^{0.05 t}}

Multiply the numbers:

1 \cdot 10000 = 10000

= \frac{10000 ( t + 12 )}{e ^{0.05 t}}

\int \frac{e ^{\frac{1}{x}}}{x} d x

f (x) = 4 x + 65, (4, 9)

y = x, y = (x - 3), (3, 5.3)

\frac{\partial}{\partial y} (x^{\frac{1}{2}} y^{\frac{3}{2}})

\int_{0}^{y^{3}} x e^{- \frac{x}{y}} d x

What is 10000(12+t)e^{-0.05t} ?
The solution to 10000(12+t)e^{-0.05t} is (10000(t+12))/(e^{0.05t)}