What is the derivative of 3^{2x} ?

The derivative of 3^{2x} is 2ln(3)*9^x

What is the first derivative of 3^{2x} ?

The first derivative of 3^{2x} is 2ln(3)*9^x

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derivative of

3^{2 x}

2 ln (3) \cdot 9^{x}

Solution steps

\frac{d}{d x} (3^{2 x})

Simplify

3^{2 x} : 9^{x}

= \frac{d}{d x} (9^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 9^{x} ln (9)

Simplify

ln (9) : 2 ln (3)

= 2 ln (3) \cdot 9^{x}

\frac{\partial}{\partial x} (x^{2} + y^{2} - 5)

\frac{d y}{d x} = 5 y e^{x + 2}

f (x) = 2 x^{2} - 7

\int_{0}^{1} \frac{2 x}{( x ^{2} + 1 ) ^{2}} d x

x = \frac{1}{2} y^{2}, y = 1, y = - \frac{1}{2} x + 3

What is the derivative of 3^{2x} ?
The derivative of 3^{2x} is 2ln(3)*9^x
What is the first derivative of 3^{2x} ?
The first derivative of 3^{2x} is 2ln(3)*9^x