What is the derivative of (x^3/(3!)) ?

The derivative of (x^3/(3!)) is (x^2)/2

What is the first derivative of (x^3/(3!)) ?

The first derivative of (x^3/(3!)) is (x^2)/2

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\frac{d}{d x} (\frac{x ^{3}}{3 !})

\frac{x ^{2}}{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3 !})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3 !} \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3 !} \cdot 3 x^{3 - 1}

Simplify

\frac{1}{3 !} \cdot 3 x^{3 - 1} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

\int (6 x + 5)^{2} d x

b

2 y (x^{2} - y + x) d x + (x^{2} - 2 y) d y = 0

\int_{0}^{4} 2 d x

\frac{d}{d x} (tan (3 x - 1))

What is the derivative of (x^3/(3!)) ?
The derivative of (x^3/(3!)) is (x^2)/2
What is the first derivative of (x^3/(3!)) ?
The first derivative of (x^3/(3!)) is (x^2)/2