What is the derivative of tan(3x-1) ?

The derivative of tan(3x-1) is sec^2(3x-1)*3

What is the first derivative of tan(3x-1) ?

The first derivative of tan(3x-1) is sec^2(3x-1)*3

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\frac{d}{d x} (tan (3 x - 1))

sec^{2} (3 x - 1) \cdot 3

Solution steps

\frac{d}{d x} (tan (3 x - 1))

Apply the chain rule:

sec^{2} (3 x - 1) \frac{d}{d x} (3 x - 1)

= sec^{2} (3 x - 1) \frac{d}{d x} (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

= sec^{2} (3 x - 1) \cdot 3

\int - 2 x^{2} e^{8 (x^{2})} - 2 x e^{- 8 x} d x

\frac{d}{d x} (arcsin (- 4 x))

n = 0 \sum \infty \frac{2}{3 ^{n + 1}}

y^{^{''}} - b^{2} y = 0

\int \frac{ln ( 2 ) x ^{5}}{x ^{2}} d x

What is the derivative of tan(3x-1) ?
The derivative of tan(3x-1) is sec^2(3x-1)*3
What is the first derivative of tan(3x-1) ?
The first derivative of tan(3x-1) is sec^2(3x-1)*3