What is the tangent of f(x)=-x^2-7x+44,\at x=2 ?

The tangent of f(x)=-x^2-7x+44,\at x=2 is y=-11x+48

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tangent of f(x)=-x^2-7x+44,\at x=2

tangent of

f (x) = - x^{2} - 7 x + 44, at x = 2

y = - 11 x + 48

Solution steps

Find the tangent point:

(2, 26)

Find the slope of

f (x) = - x^{2} - 7 x + 44 : \frac{df ( x )}{d x} = - 2 x - 7

Compute the slope of

f (x) = - x^{2} - 7 x + 44

x = 2 : m = - 11

Find the line with slope m=

- 11

and passing through

(2, 26) : y = - 11 x + 48

y = - 11 x + 48

\int - e^{3 x} d x

\frac{2 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

\int \frac{y}{x z} d x

\frac{s + 2}{( s - 2 ) ( s + 1 )}

\int 2 x y - sin (x) d x

What is the tangent of f(x)=-x^2-7x+44,\at x=2 ?
The tangent of f(x)=-x^2-7x+44,\at x=2 is y=-11x+48