What is the integral of y/(xz) ?

The integral of y/(xz) is y/z ln|x|+C

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integral of y/(xz)

\int \frac{y}{x z} d x

\frac{y}{z} ln ∣ x ∣ + C

Solution steps

\int \frac{y}{x z} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{y}{z} \cdot \int \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{y}{z} ln ∣ x ∣

Add a constant to the solution

= \frac{y}{z} ln ∣ x ∣ + C

\frac{s + 2}{( s - 2 ) ( s + 1 )}

\int 2 x y - sin (x) d x

f (x) = (x + 1) (3 x^{2} - 5 x + 2)

y^{^{''}} - y^{^{'}} - y = 0

x \to 4 lim (2 x - 1)