What is the sum from n=1 to infinity of n(7/8)^n ?

The sum from n=1 to infinity of n(7/8)^n is converges

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sum from n=1 to infinity of n(7/8)^n

n = 1 \sum \infty n (\frac{7}{8})^{n}

converges

Solution steps

n = 1 \sum \infty n (\frac{7}{8})^{n}

Apply Series Ratio Test:

converges

= converges

x^{2} + 4 x + 5

\frac{\partial}{\partial x} (x (y - 1))

\frac{d}{d x} (x^{2} lo g_{2} (x))

(x^{3} - 25 x)^{12} (- 5)

\frac{d}{d t} (\frac{( 2 t + 1 ) ^{\frac{3}{2}}}{3})

What is the sum from n=1 to infinity of n(7/8)^n ?
The sum from n=1 to infinity of n(7/8)^n is converges