What is the first derivative of 3+x^2 ?

The first derivative of 3+x^2 is 2x

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derivative of 3+x^2

\frac{d}{d x} (3 + x^{2})

2 x

Solution steps

\frac{d}{d x} (3 + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 + 2 x

Simplify

= 2 x

y^{^{''}} + 5 y = - 180 x^{2} e^{5} x

f (x) = x - ln (x)

(- 4, - 3), (8, - 9)

\int x^{3} in (3 x) d x

\frac{d}{d y} (cos (x^{2} y))