What is the derivative of 9/(2x^2) ?

The derivative of 9/(2x^2) is -9/(x^3)

What is the first derivative of 9/(2x^2) ?

The first derivative of 9/(2x^2) is -9/(x^3)

Popular >

\frac{d}{d x} (\frac{9}{2 x ^{2}})

- \frac{9}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{9}{2 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{9}{2} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{9}{2} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{9}{2} (- 2 x^{- 2 - 1})

Simplify

\frac{9}{2} (- 2 x^{- 2 - 1}) : - \frac{9}{x ^{3}}

= - \frac{9}{x ^{3}}

\frac{d y}{d x} = 20 - y

y^{^{'}} = \frac{( t ^{2} + t y + y ^{2} )}{t ^{2}}

h \to 0 lim (48 + 12 h + h^{2})

y = \frac{2 x - 1}{3 x + 5}

n = 1 \sum \infty \frac{6}{( - 5 ) ^{n}}

What is the derivative of 9/(2x^2) ?
The derivative of 9/(2x^2) is -9/(x^3)
What is the first derivative of 9/(2x^2) ?
The first derivative of 9/(2x^2) is -9/(x^3)