What is (\partial)/(\partial x)(2x+6) ?

The answer to (\partial)/(\partial x)(2x+6) is 2

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(\partial)/(\partial x)(2x+6)

\frac{\partial}{\partial x} (2 x + 6)

2

Solution steps

\frac{\partial}{\partial x} (2 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (6)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (6) = 0

= 2 + 0

Simplify

= 2

x \to 0 + lim (\frac{( 1 + x ) ^{\frac{1}{x}}}{e})^{\frac{1}{x}}

f (x) = 3 x sin (2 x)

\int \frac{1}{x 6 - x ^{2}} d x

\int sin^{3} (\frac{x}{2}) d x

θ \to \infty lim (e^{- 3 θ} cos (θ))

What is (\partial)/(\partial x)(2x+6) ?
The answer to (\partial)/(\partial x)(2x+6) is 2