What is the first derivative of 1-x^2 ?

The first derivative of 1-x^2 is -2x

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derivative of 1-x^2

derivative of

1 - x^{2}

- 2 x

Solution steps

\frac{d}{d x} (1 - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

x \to 0 lim (x^{6} cos (\frac{3}{x}))

\frac{d Q}{d t} = - \frac{5}{980 - \frac{3 t}{10}} Q + 14.1

\int_{4}^{5} \frac{1}{x} d x

\int 9 - x d x

\frac{\partial}{\partial x} (3 x^{3})