What is the derivative of 1+tan(x) ?

The derivative of 1+tan(x) is sec^2(x)

What is the first derivative of 1+tan(x) ?

The first derivative of 1+tan(x) is sec^2(x)

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\frac{d}{d x} (1 + tan (x))

sec^{2} (x)

Solution steps

\frac{d}{d x} (1 + tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (tan (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 0 + sec^{2} (x)

Simplify

= sec^{2} (x)

\int_{0}^{4} e^{x} d x

\int_{- 2}^{0} 1 + (- 4)^{2} d x

y = cos (cos (cos (x)))

\frac{\partial}{\partial x} (9 + x ln (x y - 7))

- x^{2} - 3 x, [- 4, 4]

What is the derivative of 1+tan(x) ?
The derivative of 1+tan(x) is sec^2(x)
What is the first derivative of 1+tan(x) ?
The first derivative of 1+tan(x) is sec^2(x)