en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(2x^5)

Solution

\int \frac{1}{2 x ^{5}} d x

Solution

- \frac{1}{8 x ^{4}} + C

Solution steps

\int \frac{1}{2 x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{x ^{5}} d x

Apply the Power Rule

: - \frac{1}{4 x ^{4}}

= \frac{1}{2} (- \frac{1}{4 x ^{4}})

Simplify

\frac{1}{2} (- \frac{1}{4 x ^{4}}) : - \frac{1}{8 x ^{4}}

= - \frac{1}{8 x ^{4}}

Add a constant to the solution

= - \frac{1}{8 x ^{4}} + C

Popular Examples

limit as x approaches 0 of 4-x^2

x \to 0 lim (4 - x^{2})

taylor (x+x*cos(x)-2*sin(x))/(x^3)taylor

\frac{x + x \cdot cos ( x ) - 2 \cdot sin ( x )}{x ^{3}}

d/(d{x)}(2{x}^4+2{y}^4+{z}^4-2{x}^2{y}^2{z})

\frac{d}{d x} (2 x^{4} + 2 y^{4} + z^{4} - 2 x^{2} y^{2} z)

integral of-3/y

\int - \frac{3}{y} d y

(\partial)/(\partial x)((x-y)/(x+y)-y^3)

\frac{\partial}{\partial x} (\frac{x - y}{x + y} - y^{3})

Frequently Asked Questions (FAQ)

What is the integral of 1/(2x^5) ?
The integral of 1/(2x^5) is -1/(8x^4)+C