What is (\partial)/(\partial x)(x^2 1/(y+1)) ?

The answer to (\partial)/(\partial x)(x^2 1/(y+1)) is (2x)/(y+1)

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(\partial)/(\partial x)(x^2 1/(y+1))

\frac{\partial}{\partial x} (x^{2} \frac{1}{y + 1})

\frac{2 x}{y + 1}

Solution steps

\frac{\partial}{\partial x} (x^{2} \frac{1}{y + 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y + 1} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{y + 1} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{y + 1} \cdot 2 x^{2 - 1} : \frac{2 x}{y + 1}

= \frac{2 x}{y + 1}

y = \frac{5 x}{x - 3}, (4, 20)

\int (x^{2} + 2 y) d x

x - 2, 14 - x, 2

\int (1 - x) cos (nπ x) d x

\frac{5 s}{s ^{2} + 4}

What is (\partial)/(\partial x)(x^2 1/(y+1)) ?
The answer to (\partial)/(\partial x)(x^2 1/(y+1)) is (2x)/(y+1)