What is (\partial)/(\partial x)(mx+b) ?

The answer to (\partial)/(\partial x)(mx+b) is m

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(\partial)/(\partial x)(mx+b)

\frac{\partial}{\partial x} (m x + b)

m

Solution steps

\frac{\partial}{\partial x} (m x + b)

Treat

m, b

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (m x) + \frac{\partial}{\partial x} (b)

\frac{\partial}{\partial x} (m x) = m

\frac{\partial}{\partial x} (b) = 0

= m + 0

Simplify

= m

\int_{- \infty}^{0} e^{4 y} d y

n = 1 \sum \infty \frac{( x - 2 ) ^{n}}{n}

\frac{d y}{d x} = \frac{y - x + 5}{2 y - 2 x + 6}

\int \frac{1}{x x ^{6} - 4} d x

x \frac{d y}{d x} = y + x^{2} + y^{2}, x > 0

What is (\partial)/(\partial x)(mx+b) ?
The answer to (\partial)/(\partial x)(mx+b) is m