What is the derivative of x3^x ?

The derivative of x3^x is 3^x+ln(3)*3^xx

What is the first derivative of x3^x ?

The first derivative of x3^x is 3^x+ln(3)*3^xx

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\frac{d}{d x} (x 3^{x})

3^{x} + ln (3) \cdot 3^{x} x

Solution steps

\frac{d}{d x} (x \cdot 3^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 3^{x}

= \frac{d x}{d x} 3^{x} + \frac{d}{d x} (3^{x}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (3^{x}) = 3^{x} ln (3)

= 1 \cdot 3^{x} + 3^{x} ln (3) x

Simplify

= 3^{x} + ln (3) \cdot 3^{x} x

n = 1 \sum \infty n^{3} 2^{- n}

\int (\frac{1}{x ^{2}} + \frac{4}{x x} + 2) d x

\frac{d}{d x} (\frac{3 x}{x ^{2} - 1})

\frac{d}{d x} (\frac{5 x - 4}{3 x ^{2} + 1})

y^{^{''}} + 6 y^{^{'}} + 34 y = 0, y (0) = - 1, y^{^{'}} (0) = 13

What is the derivative of x3^x ?
The derivative of x3^x is 3^x+ln(3)*3^xx
What is the first derivative of x3^x ?
The first derivative of x3^x is 3^x+ln(3)*3^xx