What is the integral of csc^4(2x) ?

The integral of csc^4(2x) is -1/6 csc^3(2x)cos(2x)-1/3 cot(2x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of csc^4(2x)

\int csc^{4} (2 x) d x

- \frac{1}{6} csc^{3} (2 x) cos (2 x) - \frac{1}{3} cot (2 x) + C

Solution steps

\int csc^{4} (2 x) d x

Apply u-substitution

: \int csc^{4} (u) \frac{1}{2} d u

= \int csc^{4} (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int csc^{4} (u) d u

Apply Integral Reduction

= \frac{1}{2} (- \frac{cos ( u ) csc ^{3} ( u )}{3} + \frac{2}{3} \cdot \int csc^{2} (u) d u)

\int csc^{2} (u) d u = - cot (u)

= \frac{1}{2} (- \frac{cos ( u ) csc ^{3} ( u )}{3} + \frac{2}{3} (- cot (u)))

Substitute back

u = 2 x

= \frac{1}{2} (- \frac{cos ( 2 x ) csc ^{3} ( 2 x )}{3} + \frac{2}{3} (- cot (2 x)))

Simplify

\frac{1}{2} (- \frac{cos ( 2 x ) csc ^{3} ( 2 x )}{3} + \frac{2}{3} (- cot (2 x))) : - \frac{1}{6} csc^{3} (2 x) cos (2 x) - \frac{1}{3} cot (2 x)

= - \frac{1}{6} csc^{3} (2 x) cos (2 x) - \frac{1}{3} cot (2 x)

Add a constant to the solution

= - \frac{1}{6} csc^{3} (2 x) cos (2 x) - \frac{1}{3} cot (2 x) + C

\int \frac{9 + 5 x}{1 + x ^{2}} d x

\frac{d}{d x} (3 x + x^{2})

\frac{\partial}{\partial x} (2 x (1 - x^{2} y^{2}))

\int e^{- s x} sin (x) d x

\frac{d}{d x} (4 x^{3} + 3 x^{2} + 2 x)

What is the integral of csc^4(2x) ?
The integral of csc^4(2x) is -1/6 csc^3(2x)cos(2x)-1/3 cot(2x)+C