What is the integral from 3 to infinity of 1/(x-2) ?

The integral from 3 to infinity of 1/(x-2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 3 to infinity of 1/(x-2)

\int_{3}^{\infty} \frac{1}{x - 2} d x

diverges

Solution steps

\int_{3}^{\infty} \frac{1}{x - 2} d x

Compute the indefinite integral:

\int \frac{1}{x - 2} d x = ln ∣ x - 2 ∣ + C

Compute the boundaries:

\int_{3}^{\infty} \frac{1}{x - 2} d x =

diverges

= diverges

\int x^{2} + 2 x + 3 d x

\frac{d}{d x} ((x^{2} + y^{2})^{6})

\frac{\partial}{\partial v} (\frac{u + v}{2})

y^{^{''''}} - 9 y^{^{''}} + 20 y = 0

What is the integral from 3 to infinity of 1/(x-2) ?
The integral from 3 to infinity of 1/(x-2) is diverges