What is the limit as h approaches 0 of (cos(h))/h ?

The limit as h approaches 0 of (cos(h))/h is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches 0 of (cos(h))/h

h \to 0 lim (\frac{cos ( h )}{h})

diverges

Solution steps

h \to 0 lim (\frac{cos ( h )}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{cos ( h )}{h}) = \infty

h \to 0 - lim (\frac{cos ( h )}{h}) = - \infty

= diverges

\int \frac{3 x}{9 + x ^{2}} d x

f (x) = 2^{2 x}

\int_{1}^{5} 2 r^{2} ln (r) d r

\frac{d}{d x} (ln (x^{2} + 4 x))

y = x, y = 2 - x, y = 0

What is the limit as h approaches 0 of (cos(h))/h ?
The limit as h approaches 0 of (cos(h))/h is diverges