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Popular >

(dy)/(dx)= 1/(1+x^2)

Solution

\frac{d y}{d x} = \frac{1}{1 + x ^{2}}

Solution

y = arctan (x) + c_{1}

Solution steps

\frac{d y}{d x} = \frac{1}{1 + x ^{2}}

Substitute

\frac{d y}{d x}

with

y^{'} (x)

y^{^{'}} (x) = \frac{1}{1 + x ^{2}}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{1}{1 + x ^{2}} d x

\int \frac{1}{1 + x ^{2}} d x = arctan (x) + c_{1}

y = arctan (x) + c_{1}

Popular Examples

limit as x approaches 0 of 5/(1-e^{1/x)}

x \to 0 lim (\frac{5}{1 - e ^{\frac{1}{x}}})

16 y^{^{''}} + 11 y = 0

integral of (e^{2x})/(e^x-1)

\int \frac{e ^{2 x}}{e ^{x} - 1} d x

integral from 0 to 1 of x/(1+x^2)

\int_{0}^{1} \frac{x}{1 + x ^{2}} d x

maclaurin 4cos(x)maclaurin

4 cos (x)

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dx)= 1/(1+x^2) ?
The solution for (dy)/(dx)= 1/(1+x^2) is y=arctan(x)+c_{1}