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Popular >

y^'=t^2y^2

Solution

y^{^{'}} = t^{2} y^{2}

Solution

y = - \frac{3}{t ^{3} + c _{1}}

Solution steps

y^{'} (t) = t^{2} y^{2}

Solve separable ODE:

y = - \frac{3}{t ^{3} + c _{1}}

y = - \frac{3}{t ^{3} + c _{1}}

Popular Examples

derivative of f(x)=2x^3-6x^2 derivative of

f (x) = 2 x^{3} - 6 x^{2}

integral of (sin^4(x))/4

\int \frac{sin ^{4} ( x )}{4} d x

integral of 1/(2+y)

\int \frac{1}{2 + y} d y

integral of (-2x^3+12x^2-20x+8.5)

\int (- 2 x^{3} + 12 x^{2} - 20 x + 8.5) d x

limit as x approaches 2 of (x^2-2x)/x

x \to 2 lim (\frac{x ^{2} - 2 x}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=t^2y^2 ?
The solution for y^'=t^2y^2 is y=-3/(t^3+c_{1)}