What is (\partial)/(\partial x)(-1-2x) ?

The answer to (\partial)/(\partial x)(-1-2x) is -2

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(\partial)/(\partial x)(-1-2x)

\frac{\partial}{\partial x} (- 1 - 2 x)

- 2

Solution steps

\frac{\partial}{\partial x} (- 1 - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (1) - \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (2 x) = 2

= - 0 - 2

Simplify

= - 2

(e^{- t})^{^{'}}

- 10 e^{- x^{2}} x

y^{^{'}} = \frac{y + t ^{3}}{t}

\int_{1}^{2} \frac{7}{x ^{3} + 3 x} d x

y^{^{'''}} + 12 y^{^{''}} + 36 y^{^{'}} = 18 x^{2}

What is (\partial)/(\partial x)(-1-2x) ?
The answer to (\partial)/(\partial x)(-1-2x) is -2