What is the derivative of x+sqrt(2x) ?

The derivative of x+sqrt(2x) is 1+1/(sqrt(2)\sqrt{x)}

What is the first derivative of x+sqrt(2x) ?

The first derivative of x+sqrt(2x) is 1+1/(sqrt(2)\sqrt{x)}

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\frac{d}{d x} (x + 2 x)

1 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + 2 x)

Simplify

x + 2 x : x + 2 x

= \frac{d}{d x} (x + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (2 x)

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x) = \frac{1}{2 x}

= 1 + \frac{1}{2 x}

\frac{\partial}{\partial x} (x e^{- x^{2}})

y = sec (x) - 2 cos (x), (\frac{π}{3}, 1)

n = 0 \sum \infty (0.7)^{n}

\frac{sec ( y )}{y ^{8}}

\int \frac{1}{e ^{x} ( e ^{x} + 1 )} d x

What is the derivative of x+sqrt(2x) ?
The derivative of x+sqrt(2x) is 1+1/(sqrt(2)\sqrt{x)}
What is the first derivative of x+sqrt(2x) ?
The first derivative of x+sqrt(2x) is 1+1/(sqrt(2)\sqrt{x)}