What is the tangent of y=sec(x)-2cos(x),(pi/3 ,1) ?

The tangent of y=sec(x)-2cos(x),(pi/3 ,1) is y=3sqrt(3)x+1-sqrt(3)pi

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tangent of y=sec(x)-2cos(x),(pi/3 ,1)

tangent of

y = sec (x) - 2 cos (x), (\frac{π}{3}, 1)

y = 33 x + 1 - 3 π

Solution steps

Find the slope of

y = sec (x) - 2 cos (x) : \frac{d y}{d x} = sec (x) tan (x) + 2 sin (x)

Compute the slope of

y = sec (x) - 2 cos (x)

(\frac{π}{3}, 1) : m = 33

Find the line with slope m=

33

and passing through

(\frac{π}{3}, 1) : y = 33 x + 1 - 3 π

y = 33 x + 1 - 3 π

n = 0 \sum \infty (0.7)^{n}

\frac{sec ( y )}{y ^{8}}

\int \frac{1}{e ^{x} ( e ^{x} + 1 )} d x

((x - 2)^{2})^{^{'}}

y^{^{'}} = \frac{2 x}{cos ( y )}

What is the tangent of y=sec(x)-2cos(x),(pi/3 ,1) ?
The tangent of y=sec(x)-2cos(x),(pi/3 ,1) is y=3sqrt(3)x+1-sqrt(3)pi