What is the solution for y^'=(2x)/(cos(y)) ?

The solution for y^'=(2x)/(cos(y)) is y=arcsin(x^2+c_{1})+2pin,y=pi+arcsin(-x^2-c_{1})+2pin

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y^'=(2x)/(cos(y))

y^{^{'}} = \frac{2 x}{cos ( y )}

y = arcsin (x^{2} + c_{1}) + 2 πn, y = π + arcsin (- x^{2} - c_{1}) + 2 πn

Solution steps

y^{'} (x) = \frac{2 x}{cos ( y )}

Solve separable ODE:

y = arcsin (x^{2} + c_{1}) + 2 πn, y = π + arcsin (- x^{2} - c_{1}) + 2 πn

y = arcsin (x^{2} + c_{1}) + 2 πn, y = π + arcsin (- x^{2} - c_{1}) + 2 πn

\int_{0}^{1.25} 1000 x d x

y^{^{''}} + y^{^{'}} + 6 y = 0

y^{^{''}} + 3 y^{^{'}} + 2 y = \frac{1}{8 + e ^{x}}

(4^{x})^{9}

What is the solution for y^'=(2x)/(cos(y)) ?
The solution for y^'=(2x)/(cos(y)) is y=arcsin(x^2+c_{1})+2pin,y=pi+arcsin(-x^2-c_{1})+2pin