What is the derivative of (x-1/x (x^2-1/x-4)) ?

The derivative of (x-1/x (x^2-1/x-4)) is 3x^2-2/(x^3)-4/(x^2)-5

What is the first derivative of (x-1/x (x^2-1/x-4)) ?

The first derivative of (x-1/x (x^2-1/x-4)) is 3x^2-2/(x^3)-4/(x^2)-5

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Popular >

\frac{d}{d x} ((x - \frac{1}{x}) (x^{2} - \frac{1}{x} - 4))

3 x^{2} - \frac{2}{x ^{3}} - \frac{4}{x ^{2}} - 5

Solution steps

\frac{d}{d x} ((x - \frac{1}{x}) (x^{2} - \frac{1}{x} - 4))

Simplify

(x - \frac{1}{x}) (x^{2} - \frac{1}{x} - 4) : x^{3} - 1 - 5 x + \frac{1}{x ^{2}} + \frac{4}{x}

= \frac{d}{d x} (x^{3} - 1 - 5 x + \frac{1}{x ^{2}} + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (1) - \frac{d}{d x} (5 x) + \frac{d}{d x} (\frac{1}{x ^{2}}) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (1) = 0

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (\frac{1}{x ^{2}}) = - \frac{2}{x ^{3}}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 3 x^{2} - 0 - 5 - \frac{2}{x ^{3}} - \frac{4}{x ^{2}}

Simplify

= 3 x^{2} - \frac{2}{x ^{3}} - \frac{4}{x ^{2}} - 5

\frac{d}{d x} (0.6 x^{2})

\frac{x}{1 - x ^{2}}

\int x^{2} e^{2 x^{3}} d x

x \to + 6 lim (8)

\int \frac{ln ^{3} ( x )}{x ^{2}} d x

What is the derivative of (x-1/x (x^2-1/x-4)) ?
The derivative of (x-1/x (x^2-1/x-4)) is 3x^2-2/(x^3)-4/(x^2)-5
What is the first derivative of (x-1/x (x^2-1/x-4)) ?
The first derivative of (x-1/x (x^2-1/x-4)) is 3x^2-2/(x^3)-4/(x^2)-5