What is the derivative of y=3-2x^2 ?

The derivative of y=3-2x^2 is -4x

What is the first derivative of y=3-2x^2 ?

The first derivative of y=3-2x^2 is -4x

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derivative of

y = 3 - 2 x^{2}

- 4 x

Solution steps

\frac{d}{d x} (3 - 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3) - \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (3) = 0

\frac{d}{d x} (2 x^{2}) = 4 x

= 0 - 4 x

Simplify

= - 4 x

2 x + 1

\frac{d}{d x} (e^{3 x} sin (x^{2}))

7 x^{2}, x^{2} + 3

x \to 3 lim (\frac{x ^{2} - 9}{3 - x})

y^{^{''}} - 8 y^{^{'}} + 16 y = 0

What is the derivative of y=3-2x^2 ?
The derivative of y=3-2x^2 is -4x
What is the first derivative of y=3-2x^2 ?
The first derivative of y=3-2x^2 is -4x