What is the derivative of 4/(1-x) ?

The derivative of 4/(1-x) is 4/((1-x)^2)

What is the first derivative of 4/(1-x) ?

The first derivative of 4/(1-x) is 4/((1-x)^2)

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\frac{d}{d x} (\frac{4}{1 - x})

\frac{4}{( 1 - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{1 - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((1 - x)^{- 1})

Apply the chain rule:

- \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

= - \frac{1}{( 1 - x ) ^{2}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 4 (- \frac{1}{( 1 - x ) ^{2}} (- 1))

Simplify

4 (- \frac{1}{( 1 - x ) ^{2}} (- 1)) : \frac{4}{( 1 - x ) ^{2}}

= \frac{4}{( 1 - x ) ^{2}}

y^{^{'}} = 13 y - y^{2} - 40

\int \frac{1}{x 9 x ^{2} - 1} d x

x^{^{'}} = \frac{1}{1 + t ^{2}}

f (x) = 4 - 2 x^{2}, at x = 5

(\frac{- 2 x - 1}{- 4 x + 2})^{5}

What is the derivative of 4/(1-x) ?
The derivative of 4/(1-x) is 4/((1-x)^2)
What is the first derivative of 4/(1-x) ?
The first derivative of 4/(1-x) is 4/((1-x)^2)