What is the tangent of f(x)=x^2-1/x ,(-1,2) ?

The tangent of f(x)=x^2-1/x ,(-1,2) is y=-x+1

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tangent of f(x)=x^2-1/x ,(-1,2)

tangent of

f (x) = x^{2} - \frac{1}{x}, (- 1, 2)

y = - x + 1

Solution steps

Find the slope of

f (x) = x^{2} - \frac{1}{x} : \frac{df ( x )}{d x} = 2 x + \frac{1}{x ^{2}}

Compute the slope of

f (x) = x^{2} - \frac{1}{x}

(- 1, 2) : m = - 1

Find the line with slope m=

- 1

and passing through

(- 1, 2) : y = - x + 1

y = - x + 1

h \to 0 lim (\frac{( h + 2 ) ^{2} - 4}{h})

y = \frac{2 x}{x + 5}, (5, 1)

\frac{d ^{2}}{d x ^{2}} (3 x^{2} - 5 y^{2})

\frac{d}{d x} (1 + 6 x)

x - 2

What is the tangent of f(x)=x^2-1/x ,(-1,2) ?
The tangent of f(x)=x^2-1/x ,(-1,2) is y=-x+1