What is the derivative of 0.0018425(t+7)^{4.5} ?

The derivative of 0.0018425(t+7)^{4.5} is 0.00829125(t+7)^{3.5}

What is the first derivative of 0.0018425(t+7)^{4.5} ?

The first derivative of 0.0018425(t+7)^{4.5} is 0.00829125(t+7)^{3.5}

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derivative of

0.0018425 (t + 7)^{4.5}

0.00829125 (t + 7)^{3.5}

Solution steps

\frac{d}{d t} (0.0018425 (t + 7)^{4.5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.0018425 \frac{d}{d t} ((t + 7)^{4.5})

Apply the chain rule:

4.5 (t + 7)^{3.5} \frac{d}{d t} (t + 7)

= 4.5 (t + 7)^{3.5} \frac{d}{d t} (t + 7)

\frac{d}{d t} (t + 7) = 1

= 0.0018425 \cdot 4.5 (t + 7)^{3.5} \cdot 1

Simplify

= 0.00829125 (t + 7)^{3.5}

y = x^{2} ln (2 x)

\int \frac{1 - x}{x} d x

\frac{d}{d x} (3 x^{2} + \frac{2}{x})

\frac{d}{d x} (2 x - y)

\int x^{2} - y^{2} d x

What is the derivative of 0.0018425(t+7)^{4.5} ?
The derivative of 0.0018425(t+7)^{4.5} is 0.00829125(t+7)^{3.5}
What is the first derivative of 0.0018425(t+7)^{4.5} ?
The first derivative of 0.0018425(t+7)^{4.5} is 0.00829125(t+7)^{3.5}