What is the solution for x^'=x^2e^{-2t} ?

The solution for x^'=x^2e^{-2t} is x=-(2e^{2t})/(-1+2c_{1)e^{2t}}

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x^'=x^2e^{-2t}

x^{^{'}} = x^{2} e^{- 2 t}

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

Solution steps

x^{'} (t) = x^{2} e^{- 2 t}

Solve separable ODE:

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

x = - \frac{2 e ^{2 t}}{- 1 + 2 c _{1} e ^{2 t}}

\int_{0}^{1} (x - e^{x})^{2} d x

\int \frac{1}{( t + 1 ) ^{2}} d t

\int_{0}^{1} \frac{3}{1 - x ^{2}} d x

f (x) = 3 x + 3 x

x \to 0 lim (\frac{∣ x - 2 ∣}{x})

What is the solution for x^'=x^2e^{-2t} ?
The solution for x^'=x^2e^{-2t} is x=-(2e^{2t})/(-1+2c_{1)e^{2t}}