What is the d/(d{r)}(2/({r)^3}) ?

The d/(d{r)}(2/({r)^3}) is -6/({r)^4}

What is the first d/(d{r)}(2/({r)^3}) ?

The first d/(d{r)}(2/({r)^3}) is -6/({r)^4}

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\frac{d}{d r} (\frac{2}{r ^{3}})

- \frac{6}{r ^{4}}

Solution steps

\frac{d}{d r} (\frac{2}{r ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d r} (\frac{1}{r ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d r} (r^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 3 r^{- 3 - 1})

Simplify

2 (- 3 r^{- 3 - 1}) : - \frac{6}{r ^{4}}

= - \frac{6}{r ^{4}}

y^{^{''}} + 10 y^{^{'}} + 41 y = 0

\int (x^{2} + 2) e^{- x} d x

n = 3 \sum \infty 4^{(n + 2)}

\int \frac{x ^{2} + x + 1}{x} d x

(1 + x y) y^{^{'}} + y^{2} = 0

What is the d/(d{r)}(2/({r)^3}) ?
The d/(d{r)}(2/({r)^3}) is -6/({r)^4}
What is the first d/(d{r)}(2/({r)^3}) ?
The first d/(d{r)}(2/({r)^3}) is -6/({r)^4}