What is the solution for (13+x^2)y^'-2xy=0 ?

The solution for (13+x^2)y^'-2xy=0 is y=13e^{c_{1}}+e^{c_{1}}x^2

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(13+x^2)y^'-2xy=0

(13 + x^{2}) y^{^{'}} - 2 x y = 0

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(13 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

y = 13 e^{c_{1}} + e^{c_{1}} x^{2}

\frac{\partial}{\partial x} (y x + 2 x + g (y))

y^{^{'}} = - x y

f (x) = x^{3} - 2 x + 2, at x = 3

\frac{\partial}{\partial x} (ln (a x + b y) + c^{x + y})

\int \frac{cos ( x )}{sin ^{2} ( x )} d x

What is the solution for (13+x^2)y^'-2xy=0 ?
The solution for (13+x^2)y^'-2xy=0 is y=13e^{c_{1}}+e^{c_{1}}x^2