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Popular >

y^'=-xy

Solution

y^{^{'}} = - x y

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}}

Solution steps

y^{'} (x) = - x y

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}}

y = e^{- \frac{x ^{2}}{2} + c_{1}}

Popular Examples

tangent of f(x)=x^3-2x+2,\at x=3 tangent of

f (x) = x^{3} - 2 x + 2, at x = 3

(\partial)/(\partial x)(ln(ax+by)+c^{x+y})

\frac{\partial}{\partial x} (ln (a x + b y) + c^{x + y})

integral of (cos(x))/(sin^2(x))

\int \frac{cos ( x )}{sin ^{2} ( x )} d x

integral of e^{2x}-e^x

\int e^{2 x} - e^{x} d x

inverse oflaplace a/(s+a)inverse laplace

\frac{a}{s + a}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-xy ?
The solution for y^'=-xy is y=e^{-(x^2)/2+c_{1}}