What is the integral from 2 to 4 of 3sqrt(x) ?

The integral from 2 to 4 of 3sqrt(x) is 16-4sqrt(2)

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integral from 2 to 4 of 3sqrt(x)

\int_{2}^{4} 3 x d x

16 - 42

Decimal Notation

10.34314 \dots

Solution steps

\int_{2}^{4} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{2}^{4} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{4}

= 3 [\frac{2}{3} x^{\frac{3}{2}}]_{2}^{4}

Compute the boundaries:

\frac{16}{3} - \frac{4 2}{3}

= 3 (\frac{16}{3} - \frac{4 2}{3})

Simplify

= 16 - 42

f (x) = (3 x - 10) (2 x^{2} - x + 1)

\int 17 e^{x} d x

\int \frac{a}{x ^{3}} d x

n = 1 \sum \infty 1^{n}

\int 2 a x d x

What is the integral from 2 to 4 of 3sqrt(x) ?
The integral from 2 to 4 of 3sqrt(x) is 16-4sqrt(2)